Does anyone know how I can copy bar 13 into bar 14, or indeed write it at all? ‘r’, cmd-c cmd-v and alt-click gives strange results.
When I try to rewrite it, the triplet on beat 1 of bar 14 interferes, but if I delete it, bar 13 changes.
Despite many attempts, I unfortunately can’t get the hang of it.
Thanks for help.
Just to be safe, I would first select bar 14 and hit delete (that will remove the initial tuplet). Then select bar 13 and hit R.
My guess is that those two triplets are attached is because you actually have a quarter note triplet across the m
barline. Try rewriting beat 4 of m 13 explicitly as 3e:2e, then entering that tied quarter note. Then you should be able to select the whole measure and R or alt+click.
I think.
Thanks, Janus!
This is the result after deleting bar
This is the result after deleting twice
This is the result after copying by R
This is the result after replacing it by opt-left arrow
I will now try the proposal of alanpolacek
Thank you, alanpolacek, but the result is the same:
erasing bar 14 and count 4 of b 13. Rewriting it as you said.
Result after typing R:
Result after replacing:
I entered a “clean” copy of your first measure, with no “dangling” tuplet in the second measure. R worked as expected:
Nope - I cannot replicate your result. It works perfectly for me.
Sorry. You must be doing something different.
When writing a bar such as 13, here’s what often happens: At beat 4 you need a triplet, so you enter 3 (or 3:2) in the popover. But if you don’t specify the note value with 3:2e for eighth note, Dorico creates a quarter note triplet because you had a quarter note selected! This triplet is 2 quarters long, and thus spans the barline, into the first beat of bar 14. But it appears as two eighth note triplets by default, because Dorico offers that feature.
When you have these two triplets and you click on either one, both of them highlight. This is your clue that they are actually one triplet spanning the barline.
As Alan said, the way to handle this is to enter an eighth note triplet in the first place. (BTW, there’s no need for another “e” before the colon. Dorico makes ratios of only the same note value anyway.)
I hope not. The presenting problem was about repeating a bar, not about the cause of the cross barline tuplet.
Selecting bar 13 in the OP makes a selection 5 beats long. R repeats that selection after it. You can’t delete the tuplet that appears in 14 without losing the tuplet in 13. Recreating the tuplet the same way without understanding how the mistake happened gets us nowhere.
Case solved. Thanks to all the helpers. I had a fundamental misunderstanding that stubbornly carried over from my Sibelius days. In Sibelius you write a quarter note and press cmd-3, then you have 3 quaver triplets. Dorico is more generous and writes six! This was difficult for me to understand and thanks to your help I have now realised it.
I would like to add something unpleasant:
I write lengths and pitches via the keyboard and have the 3:2 function on one key. This is ineffective - it only opens the popover and I would have to make further entries on the QWERTY-keyboard.
So my only option is to grab the mouse and activate 3:2 on the left of the screen.
Is there any other way to activate and deactivate this 3:2 than to grab the mouse again and search for and delete this point? In my opinion, this is clumsy and time-consuming, especially if you have heavily mixed music text.
I’m not clear on exactly what you’re doing, but here’s what I generally do:
@Stentor, in the event that any more on this is even needed/helpful 
…:
One thing that (for some reason) took me a bit to get used to is that after entering the quarter on beat 3 you can enter 5 to switch to an eighth to “seed” the correct triplet, then — because the beat-3 quarter is still selected — extend that note to fill 2/3 of the triplet.
Yes, that’s the best way.
And even trickier, but just as effective, for this particular rhythm:
Thanks @Juddanby and @ Mark Johnson: 24 hours ago I was faced with a problem I couldn’t solve, and now I see that there are many roads to Rome. However, they are different lengths and Mark’s way requires about 8 clicks per triplet, which is quite time-consuming if you have to alternate between binary and ternary rhythms. Mark also mentioned it as a second priority. I have found one consolation: instead of writing “3:2e” in the popover, “3e” is enough. At least 3 keystrokes less…
A suggestion to Dorico for help with shortcuts: I don’t know which country you’re writing to me from, but here in Switzerland the letter ‘ ö “ (which is probably only used in the Arctic) takes the place of your ” ; ’. I used to avoid the shortcut list because I had to translate almost every keystroke on my keyboard or change the keyboard layout. Wouldn’t it be more practical if Steinberg labelled line and column instead of ‘national’ letters - Dorico is an international programme, isn’t it? Using the ‘Neanderthal method’, I found out that ; = ö. That would be key ‘C-10’ in the ‘spatial’ designation. Would that work for you, favoured ones, with the correct keyboard layout?
Thanks for your judgement!
U.S. for both Mark and me.
Aha!
The workings of keyboard mappings are way over my head, @Stentor. A member of the Dorico team or another member more versed in that will no doubt “chime in” on this.
I’m not sure how you’re doing it, but for me it’s 4 keystrokes, 3 to start triplets and 1 to stop them. If you’re clicking things with the mouse, that is definitely slower and more cumbersome. If you’ve been avoiding keyboard shortcuts because of confusion about keyboard mapping …
Hope this helps!
