I’m trying to write Scriabin’s Op.31, but I can’t understand how to do it. There seem to be triplets in the section written for the left hand, but I can’t figure out how to do it.
It looks like 9 quavers in the space of 6 ; then you’ve got to adjust the beam grouping.
“If it’s too hard: I can’t understand it.”
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I attempted Scriabin’s Op. 11, No. 19 a few years ago. The entire thing was full of hidden tuplets and manual beaming.
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Thak you very much
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In the space of 6, no? (The meter being 3/4.) Thus a triplet on each beat. (With an additional L.H. triplet note before the R.H. commences, not-quite-accurately covered by the initial quaver rest.)
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Yes. Schoolboy counting error. 
The triplets are, of course, on the beat, and then the beaming is changed. Also the very first eighth note appears to be not in a triplet. Once you’ve got a full bar of these triplets beamed as desired, you can select of them and duplicate until they fill all 32 bars, and then just repitch them to the correct notes!