I have a problem with a tuplet. The first screenshot shows what is shown in the official score. This part of the score is in ¾ time signature with treble clef.
I count 3 x 1/16 + ¼ = 4x 1/16. So 7 x 1/16. So how can this be shown as a triplet as in the score?
I can show the first measure as a 7:16 or as 3:8 triplet but then I have to shorten the C to a dotted 8th. I show the two options in the following screenshot
I’d say that the original score could be engraved a bit better, because I think the triplet is not enclosing the minim, although it looks it almost does.
To answer the question of OP, I would do a 6:4x tuplet and then inside of it add a nested 3:2x tuplet (x means 16th).
Then hide the 6:4 tuplet and voila
My guess is that the source score is badly written / or badly copied.
It might be as simple as: those “triplets” are supposed to be appoggiaturas in the 3/4 meter…
Someone might have used this “tuplet function” because they did not know how to write appoggiaturas… and there is Software around that does not complain if a bar is overfilled…
Many thanks both. Very good idea with the two levels of tuplets. When I just hide the 3 above the 3x 1/16 note it is exactly as in the score.
It is an “official” John Williams signature edition. I have already copied a lot out of those to Dorico but never found an error. It has the most incredible tuplet combinations which sometimes need some calculation. I just find that the percussion is often too condensed. It probably needs more players than the number of percussion staffs in most of these scores…
A lot of work however as all is written without key signature in transposed pitch. So a lot accidentals.
No there are only 4 measures in the harp and piano staffs of this 200 measure, full orchestra piece with this note scheme. They are in a sequence of three and one a bit further on.